更新 workspace.xml

.idea/workspace.xml

@@ -5,7 +5,8 @@
   </component>
   <component name="ChangeListManager">
     <list default="true" id="45f625e1-36c7-4942-8f7c-ba3ebe9a7d53" name="变更" comment="">
-      <change beforePath="$PROJECT_DIR$/.gitignore" beforeDir="false" afterPath="$PROJECT_DIR$/.gitignore" afterDir="false" />
+      <change beforePath="$PROJECT_DIR$/src/solution/Solution.java" beforeDir="false" afterPath="$PROJECT_DIR$/src/solution/Solution.java" afterDir="false" />
+      <change beforePath="$PROJECT_DIR$/src/solution/test.java" beforeDir="false" afterPath="$PROJECT_DIR$/src/solution/test.java" afterDir="false" />
     </list>
     <option name="SHOW_DIALOG" value="false" />
     <option name="HIGHLIGHT_CONFLICTS" value="true" />
@@ -76,22 +77,11 @@
       <option name="presentableId" value="Default" />
       <updated>1693822719192</updated>
       <workItem from="1693822720224" duration="5742000" />
-      <workItem from="1693895305007" duration="5192000" />
+      <workItem from="1693895305007" duration="5324000" />
     </task>
     <servers />
   </component>
   <component name="TypeScriptGeneratedFilesManager">
     <option name="version" value="3" />
   </component>
-  <component name="XDebuggerManager">
-    <breakpoint-manager>
-      <breakpoints>
-        <line-breakpoint enabled="true" type="java-line">
-          <url>file://$PROJECT_DIR$/src/solution/test.java</url>
-          <line>38</line>
-          <option name="timeStamp" value="4" />
-        </line-breakpoint>
-      </breakpoints>
-    </breakpoint-manager>
-  </component>
 </project>

src/solution/Solution.java

@@ -8,7 +8,7 @@ import java.util.Set;
 public class Solution {
 
     //给定一个字符串 s ，找出其中不含有重复字符的 最长子串 的长度。
-    public int lengthOfLongestSubstring(String s) {
+    public static int lengthOfLongestSubstring(String s) {
         // 哈希集合，记录每个字符是否出现过
         Set<Character> occ = new HashSet<Character>();
         int n = s.length();
@@ -52,7 +52,7 @@ public class Solution {
 
 
     //哈希映射算法（Hash Mapping Algorithm）用于找出一个数组中的众数（majority element）
-    public int majorityElement(int[] nums) {
+    public static int majorityElement(int[] nums) {
         Map<Integer, Integer> map = new HashMap<>();
         // maxNum 表示元素，maxCount 表示元素出现的次数
         int maxNum = 0, maxCount = 0;

src/solution/test.java

@@ -6,34 +6,6 @@ import java.util.Set;
 
 public class test {
     public static void main(String[] args) {
-        String s = "bbbbb";
-        String s1 = "abcabcbb";
-        String s2 = "pwwkew";
-        String s3 = "ckilbkd";
-        String s4 = "dvdf";
-        System.out.println(lengthOfLongestSubstring(s3));
-
+        
     }
-    public static int lengthOfLongestSubstring(String s) {
-        // 哈希集合，记录每个字符是否出现过
-        Set<Character> occ = new HashSet<Character>();
-        int n = s.length();
-        // 右指针，初始值为 -1，相当于我们在字符串的左边界的左侧，还没有开始移动
-        int rk = -1, ans = 0;
-        for (int i = 0; i < n; ++i) {
-            if (i != 0) {
-                // 左指针向右移动一格，移除一个字符
-                occ.remove(s.charAt(i - 1));
-            }
-            while (rk + 1 < n && !occ.contains(s.charAt(rk + 1))) {
-                // 不断地移动右指针
-                occ.add(s.charAt(rk + 1));
-                ++rk;
-            }
-            // 第 i 到 rk 个字符是一个极长的无重复字符子串
-            ans = Math.max(ans, rk - i + 1);
-        }
-        return ans;
-    }
-
 }