Update game_state.py
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b2d9514d2a
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f8fadb435c
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@ -1,23 +1,24 @@
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from .utils import get_suit,get_tile_name
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from loguru import logger
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from collections import Counter
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from .hand import Hand
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from .mahjong_tile import MahjongTile
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class ChengduMahjongState:
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def __init__(self):
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# 每个玩家的手牌,使用108个索引表示
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self.hands = [[0] * 108 for _ in range(4)] # 每个玩家108张牌的计数
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# 每个玩家的手牌
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self.hands = [Hand() for _ in range(4)] # 每个玩家的手牌由 Hand 类表示
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# 每个玩家的打出的牌
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self.discards = [[] for _ in range(4)] # 每个玩家的弃牌列表
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# 每个玩家的明牌(碰、杠)
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self.melds = [[] for _ in range(4)]
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# 剩余的牌堆
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self.deck = list(range(108)) # 0-107 表示108张牌
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self.deck = [MahjongTile(suit, value) for suit in ["条", "筒", "万"] for value in range(1, 10)] * 4 # 108张牌
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# 当前玩家索引
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self.current_player = 0
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# 玩家分数
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self.scores = [100, 100, 100, 100]
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# 剩余牌数量
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self.remaining_tiles = 108
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self.remaining_tiles = len(self.deck)
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# 胜利玩家列表
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self.winners = []
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# 缺门信息
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@ -39,21 +40,20 @@ class ChengduMahjongState:
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raise ValueError("缺门设置无效")
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self.missing_suits[player] = missing_suit
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def can_win(self, hand):
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def can_win(self, hand: Hand):
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"""
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判断是否满足胡牌条件:四组(顺子或刻子)+ 一对将。
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"""
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from collections import Counter
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def is_valid_group(tiles):
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"""
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判断是否为合法的顺子或刻子。
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"""
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if len(tiles) != 3:
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return False
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tiles.sort() # 确保顺子检查按顺序排列
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tiles.sort(key=lambda t: (t.suit, t.value))
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return (tiles[0] == tiles[1] == tiles[2]) or \
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(tiles[0] + 1 == tiles[1] and tiles[1] + 1 == tiles[2])
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(tiles[0].value + 1 == tiles[1].value and tiles[1].value + 1 == tiles[2].value and
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tiles[0].suit == tiles[1].suit == tiles[2].suit)
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def try_win(remaining_tiles, depth=0):
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"""
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@ -69,21 +69,22 @@ class ChengduMahjongState:
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if is_valid_group(group):
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next_tiles = remaining_tiles[:i] + remaining_tiles[i + 1:j] + \
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remaining_tiles[j + 1:k] + remaining_tiles[k + 1:]
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# 确保顺子检查按顺序排列
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next_tiles.sort()
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if try_win(next_tiles, depth + 1):
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return True
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return False
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counter = Counter({tile: count for tile, count in enumerate(hand) if count > 0})
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pairs = [tile for tile, count in counter.items() if count >= 2]
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# 统计每张牌的数量
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tile_counter = Counter(hand.tiles)
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pairs = [tile for tile, count in tile_counter.items() if count >= 2]
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for pair in pairs:
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temp_hand = hand[:]
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temp_hand[pair] -= 2 # 移除将牌
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remaining_tiles = [tile for tile, count in enumerate(temp_hand) for _ in range(count)]
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remaining_tiles.sort() # 确保顺子检查按顺序排列
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if try_win(remaining_tiles):
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# 移除一对将牌
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temp_tiles = hand.tiles[:]
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temp_tiles.remove(pair)
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temp_tiles.remove(pair)
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# 检查剩余牌是否能分组
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if try_win(temp_tiles):
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return True
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return False
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